p^2=891

Solution for p^2=891 equation:

p^2=891

We move all terms to the left:

p^2-(891)=0

a = 1; b = 0; c = -891;
Δ = b2-4ac
Δ = 02-4·1·(-891)
Δ = 3564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3564}=\sqrt{324*11}=\sqrt{324}*\sqrt{11}=18\sqrt{11}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{11}}{2*1}=\frac{0-18\sqrt{11}}{2}
=-\frac{18\sqrt{11}}{2}
=-9\sqrt{11}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{11}}{2*1}=\frac{0+18\sqrt{11}}{2}
=\frac{18\sqrt{11}}{2}
=9\sqrt{11}
$